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Siemens Application Project + STL to LAD conversion

 
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King_gen
Junior
Junior


Joined: 21 Jun 2015
Posts: 13
PostPosted: 20/07/2015 22:21    Post subject: Siemens Application Project + STL to LAD conversion Reply with quote
Can someone upload a link to a real life project using siemens STEP 7.Also,can someone convert this STL into LAD for me or explain to me how I would go about converting it.

A M 0.1
BEC
L 0
T DB10.DBW 4
AN I 1.5
R DB10.DBX 3.0
R DB10.DBX 3.1
AN I 1.4
= DB10.DBX 4.0
A(
A Q 100.0
O Q 100.1
)
= DBX 5.2
A I 0.5
= DBX 5.0
A Q 87.0
= DBX 5.1


ALSO:


L QB 86
L B#16#F8
AW
T #TEMP11
L QB 86
L DB22.DBB 5
AW
L 0
<>I
JC M001
M003: L #TEMP11
L DBB 4
OW
T QB 86
JU M002
M001: A Q 86.0
A Q 86.1
A Q 86.2
O
A Q 86.0
A Q 86.1
O
A Q 86.0
A Q 86.2
O
A Q 86.1
A Q 86.2
JC M003
M002: L QB 86
L B#16#7
AW
T DB10.DBB 69
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maersk
Member 3
Member 3
maersk

Joined: 17 Aug 2014
Posts: 891
PostPosted: 21/07/2015 18:40    Post subject: Re: Siemens Application Project + STL to LAD conversion Reply with quote
King_gen wrote:
Can someone upload a link to a real life project using siemens STEP 7.Also,can someone convert this STL into LAD for me or explain to me how I would go about converting it.

Code:
 A     M      0.1
      BEC   
      L     0
      T     DB10.DBW    4
      AN    I      1.5
      R     DB10.DBX    3.0
      R     DB10.DBX    3.1
      AN    I      1.4
      =     DB10.DBX    4.0
      A(   
      A     Q    100.0
      O     Q    100.1
      )     
      =     DBX    5.2
      A     I      0.5
      =     DBX    5.0
      A     Q     87.0
      =     DBX    5.1


ALSO:


Code:
L     QB    86
      L     B#16#F8
      AW   
      T     #TEMP11
      L     QB    86
      L     DB22.DBB    5
      AW   
      L     0
      <>I   
      JC    M001
M003: L     #TEMP11
      L     DBB    4
      OW   
      T     QB    86
      JU    M002
M001: A     Q     86.0
      A     Q     86.1
      A     Q     86.2
      O     
      A     Q     86.0
      A     Q     86.1
      O     
      A     Q     86.0
      A     Q     86.2
      O     
      A     Q     86.1
      A     Q     86.2
      JC    M003
M002: L     QB    86
      L     B#16#7
      AW   
      T     DB10.DBB   69

Find examples on this link.
http://plc.myforum.ro/application-examples-vf33.html

STL to LAD Conversion I'm afraid it's not possible. There are some instructions which cannot be converted on LAD.
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maersk
Member 3
Member 3
maersk

Joined: 17 Aug 2014
Posts: 891
PostPosted: 21/07/2015 18:41    Post subject: Re: Siemens Application Project + STL to LAD conversion Reply with quote
King_gen wrote:
Can someone upload a link to a real life project using siemens STEP 7.Also,can someone convert this STL into LAD for me or explain to me how I would go about converting it.

Code:
 A     M      0.1
      BEC   
      L     0
      T     DB10.DBW    4
      AN    I      1.5
      R     DB10.DBX    3.0
      R     DB10.DBX    3.1
      AN    I      1.4
      =     DB10.DBX    4.0
      A(   
      A     Q    100.0
      O     Q    100.1
      )     
      =     DBX    5.2
      A     I      0.5
      =     DBX    5.0
      A     Q     87.0
      =     DBX    5.1


ALSO:


Code:
L     QB    86
      L     B#16#F8
      AW   
      T     #TEMP11
      L     QB    86
      L     DB22.DBB    5
      AW   
      L     0
      <>I   
      JC    M001
M003: L     #TEMP11
      L     DBB    4
      OW   
      T     QB    86
      JU    M002
M001: A     Q     86.0
      A     Q     86.1
      A     Q     86.2
      O     
      A     Q     86.0
      A     Q     86.1
      O     
      A     Q     86.0
      A     Q     86.2
      O     
      A     Q     86.1
      A     Q     86.2
      JC    M003
M002: L     QB    86
      L     B#16#7
      AW   
      T     DB10.DBB   69

Find examples on this link.
http://plc.myforum.ro/application-examples-vf33.html

STL to LAD Conversion I'm afraid it's not possible. There are some instructions which cannot be converted on LAD.
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King_gen
Junior
Junior


Joined: 21 Jun 2015
Posts: 13
PostPosted: 21/07/2015 20:12    Post subject: Reply with quote
Code:
A M 0.1
BEC
L 0
T DB10.DBW 4
AN I 1.5
R DB10.DBX 3.0
R DB10.DBX 3.1
AN I 1.4
= DB10.DBX 4.0
A(
A Q 100.0
O Q 100.1
)
= DBX 5.2
A I 0.5
= DBX 5.0
A Q 87.0
= DBX 5.1


ALSO:


Code:
L QB 86
L B#16#F8
AW
T #TEMP11
L QB 86
L DB22.DBB 5
AW
L 0
<>I
JC M001
M003: L #TEMP11
L DBB 4
OW
T QB 86
JU M002
M001: A Q 86.0
A Q 86.1
A Q 86.2
O
A Q 86.0
A Q 86.1
O
A Q 86.0
A Q 86.2
O
A Q 86.1
A Q 86.2
JC M003
M002: L QB 86
L B#16#7
AW
T DB10.DBB 69


OK kool but can you explain the various operations that are taking place??? I`m not familiar with the syntax yet
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jfrc
Junior
Junior


Joined: 13 Mar 2014
Posts: 4
PostPosted: 22/07/2015 17:47    Post subject: Reply with quote
You can put the cursor over the instruction and press F1, it will open the help for that instruction with examples.
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gecko1
Member
Member
gecko1

Joined: 24 Nov 2013
Posts: 225
PostPosted: 23/07/2015 18:19    Post subject: Reply with quote
jfrc wrote:
You can put the cursor over the instruction and press F1, it will open the help for that instruction with examples.


SIMATIC S7-SCL V5.3 for S7-300/400
http://www.datafilehost.com/d/d80863a5
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